## What is a NEC demand factor?

## What is the feeder demand for one 15kW range?

The demand load for fifteen 15kW ranges is **34.5kW** (See Figure 2). When applying note 1, the range ratings (before applying Column C) cannot include a fraction of a kilowatt. The fraction must either be dropped, or rounded up to the next whole kilowatt rating. When the fraction is less than .

## How do you calculate electrical load demand?

To calculate your load factor take the **total electricity (KWh) used in the billing period and divide it by the peak demand (KW)**, then divide by the number of days in the billing cycle, then divide by 24 hours in a day. The result is a ratio between zero and one.

## What are Noncoincident loads?

Noncoincident loads are **two or more loads that are unlikely to be in use simultaneously**, so only the larger of the two loads must be used for the calculation.

## How is electrical diversity factor calculated?

Diversity Factor = **Sum of Individual Maximum Demands / Maximum Demand of the System**. Diversity Factor = Installed load / Running load.Oct 31, 2011

### Related questions

##### Related

### What is acceptable disconnecting for appliances?

There are several different types of acceptable disconnecting means permitted in Part III (depending on the appliance) which may include a **unit switch with a marked “off” position**, a horsepower rated snap switch, or even the branch circuit breaker.

##### Related

### What is the maximum feeder demand for two 12kW ranges?

By applying Table 220.19, a 12kW range has a maximum demand of **8kW** (See Figure 2).

##### Related

### How many KW is a range?

Most electric ovens draw between **2,000 and 5,000 watts**, with the average electric stove wattage coming in at around 3,000 watts. So how much energy does an electric stove use per hour? Assuming an electricity rate of 12 cents per kilowatt-hour (kWh), a 3000-watt oven will cost you about 36 cents per hour at high heat.

##### Related

### What is the feeder load in VA for three small appliance branch circuits?

The small--appliance and laundry branch circuit load for each unit is 4,500 VA (1,500 3 = 4,500). The small-appliance and laundry branch-circuit load for three units is **13,500 VA** (4,500 3 = 13,500).

##### Related

### What demand factor is allowed for a commercial kitchen with one electric appliance?

One piece of equipment has a **100% demand factor**, while six or more have a 65% demand factor. There is an exception to the table that is stated in the second paragraph of NEC 220.56. The total load for the kitchen equipment has to be at least as large as the sum of the two largest kitchen equipment loads.Dec 7, 2015

##### Related

### How do you calculate KW demand load?

If all appliances are the same rating, multiply the number of units by the kilowatt rating of each (12 x 7 = 84kW). Next, find the demand factor percent in Column B for 12 appliances (12 appliances = 32 percent). Now compute the demand load **by multiplying the total load by the demand factor percent** (84 x .

##### Related

### What are the requirements of the 22055 regulations?

- Requirements in 220.55 are permissive rules. For example, the load for household electric ranges, wall-mounted ovens, counter-mounted cooking units and other household cooking appliances individually rated in excess of 1¾ kW shall be permitted to be calculated in accordance with Table 220.55.

##### Related

### What is Article 220 of the National Electrical Code (NEC)?

- Article
**220**of the National Electrical Code (**NEC**) contains requirements for calculating branch-circuit, feeder and service loads. Article**220**contains a lot of these requirements, but calculating branch-circuit, feeder and service loads in accordance with every one of those requirements is not absolutely necessary.

##### Related

### Do we have to use table 220 for cooking appliances?

- For example, the load for household electric ranges, wall-mounted ovens, counter-mounted cooking units and other household cooking appliances individually rated in excess of 1¾ kW shall be permitted to be calculated in accordance with Table 220.55. We are not required to use Table 220.55. We are permitted to use the table.

##### Related

### What are the lighting load requirements under Article 220?

- This requirement states that, when calculating the lighting load, the load must not be less than the volt-ampere unit load per square foot (or square meter) that is specified in
**Table 220**.12. Some requirements in Article**220**are permissive rules.